This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
12F16 = 1 2 F = 1(=0001) 2(=0010) F(=1111) = 1001011112
the Final answer: 12F16 = 1001011112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙162+2∙161+15∙160 = 1∙256+2∙16+15∙1 = 256+32+15 = 30310
got It: 12F16 =30310
Translate the number 30310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
303 | 2 | | | | | | | | |
-302 | 151 | 2 | | | | | | | |
1 | -150 | 75 | 2 | | | | | | |
| 1 | -74 | 37 | 2 | | | | | |
| | 1 | -36 | 18 | 2 | | | | |
| | | 1 | -18 | 9 | 2 | | | |
| | | | 0 | -8 | 4 | 2 | | |
| | | | | 1 | -4 | 2 | 2 | |
| | | | | | 0 | -2 | 1 | |
| | | | | | | 0 | | |
|
the result of the conversion was:
30310 = 1001011112
the Final answer: 12F16 = 1001011112