This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
A4516 = A 4 5 = A(=1010) 4(=0100) 5(=0101) = 1010010001012
answer: A4516 = 1010010001012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+4∙161+5∙160 = 10∙256+4∙16+5∙1 = 2560+64+5 = 262910
got It: A4516 =262910
Translate the number 262910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2629 | 2 | | | | | | | | | | | |
-2628 | 1314 | 2 | | | | | | | | | | |
1 | -1314 | 657 | 2 | | | | | | | | | |
| 0 | -656 | 328 | 2 | | | | | | | | |
| | 1 | -328 | 164 | 2 | | | | | | | |
| | | 0 | -164 | 82 | 2 | | | | | | |
| | | | 0 | -82 | 41 | 2 | | | | | |
| | | | | 0 | -40 | 20 | 2 | | | | |
| | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
262910 = 1010010001012
answer: A4516 = 1010010001012