This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙162+11∙161+12∙160+4∙16-1+13∙16-2 = 10∙256+11∙16+12∙1+4∙0.0625+13∙0.00390625 = 2560+176+12+0.25+0.05078125 = 2748.3007812510
got It: ABC.4d16 =2748.3007812510
Translate the number 2748.3007812510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2748 | 8 | | | |
-2744 | 343 | 8 | | |
4 | -336 | 42 | 8 | |
| 7 | -40 | 5 | |
| | 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 30078125*8 |
2 | .40625*8 |
3 | .25*8 |
2 | .0*8 |
the result of the conversion was:
2748.3007812510 = 5274.2328
answer: ABC.4d16 = 5274.2328
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
ABC.4d16 = A B C. 4 d = A(=1010) B(=1011) C(=1100). 4(=0100) d(=1101) = 101010111100.010011012
answer: ABC.4d16 = 101010111100.010011012
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101010111100.0100110102 = 101 010 111 100. 010 011 010 = 101(=5) 010(=2) 111(=7) 100(=4). 010(=2) 011(=3) 010(=2) = 5274.2328
answer: ABC.4d16 = 5274.2328