This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙1612+0∙1611+0∙1610+0∙169+0∙168+0∙167+0∙166+0∙165+0∙164+0∙163+0∙162+0∙161+14∙160 = 0∙281474976710656+0∙17592186044416+0∙1099511627776+0∙68719476736+0∙4294967296+0∙268435456+0∙16777216+0∙1048576+0∙65536+0∙4096+0∙256+0∙16+14∙1 = 0+0+0+0+0+0+0+0+0+0+0+0+14 = 1410
got It: 000000000000E16 =1410
Translate the number 1410 в octal like this:
the Integer part of the number is divided by the base of the new number system:
14 | 8 | |
-8 | 1 | |
6 | | |
|
the result of the conversion was:
1410 = 168
answer: 000000000000E16 = 168
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
000000000000E16 = 0 0 0 0 0 0 0 0 0 0 0 0 E = 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) E(=1110) = 11102
answer: 000000000000E16 = 11102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011102 = 001 110 = 001(=1) 110(=6) = 168
answer: 000000000000E16 = 168