This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0001100110012 = 000 110 011 001 = 000(=0) 110(=6) 011(=3) 001(=1) = 06318
answer: 001100110012 = 06318
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+0∙26+0∙25+1∙24+1∙23+0∙22+0∙21+1∙20 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+0∙64+0∙32+1∙16+1∙8+0∙4+0∙2+1∙1 = 0+0+0+256+128+0+0+16+8+0+0+1 = 40910
got It: 0001100110012 =40910
Translate the number 40910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
409 | 8 | | |
-408 | 51 | 8 | |
1 | -48 | 6 | |
| 3 | | |
|
the result of the conversion was:
40910 = 6318
answer: 001100110012 = 6318