This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
3∙161+9∙160+11∙16-1+8∙16-2 = 3∙16+9∙1+11∙0.0625+8∙0.00390625 = 48+9+0.6875+0.03125 = 57.7187510
got It: 39.b816 =57.7187510
Translate the number 57.7187510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
57 | 8 | |
-56 | 7 | |
1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 71875*8 |
5 | .75*8 |
6 | .0*8 |
the result of the conversion was:
57.7187510 = 71.568
answer: 39.b816 = 71.568
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
39.b816 = 3 9. b 8 = 3(=0011) 9(=1001). b(=1011) 8(=1000) = 111001.101112
answer: 39.b816 = 111001.101112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
111001.1011102 = 111 001. 101 110 = 111(=7) 001(=1). 101(=5) 110(=6) = 71.568
answer: 39.b816 = 71.568