This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
011110002 = 0111 1000 = 0111(=7) 1000(=8) = 7816
answer: 011110002 = 7816
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙27+1∙26+1∙25+1∙24+1∙23+0∙22+0∙21+0∙20 = 0∙128+1∙64+1∙32+1∙16+1∙8+0∙4+0∙2+0∙1 = 0+64+32+16+8+0+0+0 = 12010
got It: 011110002 =12010
Translate the number 12010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
120 | 16 | |
-112 | 7 | |
8 | | |
|
the result of the conversion was:
12010 = 7816
answer: 011110002 = 7816