This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01110010110010002 = 0111 0010 1100 1000 = 0111(=7) 0010(=2) 1100(=C) 1000(=8) = 72C816
answer: 01110010110010002 = 72C816
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+1∙214+1∙213+1∙212+0∙211+0∙210+1∙29+0∙28+1∙27+1∙26+0∙25+0∙24+1∙23+0∙22+0∙21+0∙20 = 0∙32768+1∙16384+1∙8192+1∙4096+0∙2048+0∙1024+1∙512+0∙256+1∙128+1∙64+0∙32+0∙16+1∙8+0∙4+0∙2+0∙1 = 0+16384+8192+4096+0+0+512+0+128+64+0+0+8+0+0+0 = 2938410
got It: 01110010110010002 =2938410
Translate the number 2938410 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
29384 | 16 | | | |
-29376 | 1836 | 16 | | |
8 | -1824 | 114 | 16 | |
| C | -112 | 7 | |
| | 2 | | |
|
the result of the conversion was:
2938410 = 72C816
answer: 01110010110010002 = 72C816