This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0001101111112 = 000 110 111 111 = 000(=0) 110(=6) 111(=7) 111(=7) = 06778
answer: 01101111112 = 06778
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+1∙22+1∙21+1∙20 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+1∙4+1∙2+1∙1 = 0+0+0+256+128+0+32+16+8+4+2+1 = 44710
got It: 0001101111112 =44710
Translate the number 44710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
447 | 8 | | |
-440 | 55 | 8 | |
7 | -48 | 6 | |
| 7 | | |
|
the result of the conversion was:
44710 = 6778
answer: 01101111112 = 6778