This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0001101002 = 000 110 100 = 000(=0) 110(=6) 100(=4) = 0648
answer: 01101002 = 0648
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+0∙26+1∙25+1∙24+0∙23+1∙22+0∙21+0∙20 = 0∙256+0∙128+0∙64+1∙32+1∙16+0∙8+1∙4+0∙2+0∙1 = 0+0+0+32+16+0+4+0+0 = 5210
got It: 0001101002 =5210
Translate the number 5210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
52 | 8 | |
-48 | 6 | |
4 | | |
|
the result of the conversion was:
5210 = 648
answer: 01101002 = 648