This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
14∙162+7∙161+12∙160+11∙16-1 = 14∙256+7∙16+12∙1+11∙0.0625 = 3584+112+12+0.6875 = 3708.687510
got It: E7C.B16 =3708.687510
Translate the number 3708.687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3708 | 8 | | | |
-3704 | 463 | 8 | | |
4 | -456 | 57 | 8 | |
| 7 | -56 | 7 | |
| | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 6875*8 |
5 | .5*8 |
4 | .0*8 |
the result of the conversion was:
3708.687510 = 7174.548
answer: E7C.B16 = 7174.548
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
E7C.B16 = E 7 C. B = E(=1110) 7(=0111) C(=1100). B(=1011) = 111001111100.10112
answer: E7C.B16 = 111001111100.10112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
111001111100.1011002 = 111 001 111 100. 101 100 = 111(=7) 001(=1) 111(=7) 100(=4). 101(=5) 100(=4) = 7174.548
answer: E7C.B16 = 7174.548