This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
A2FCE016 = A 2 F C E 0 = A(=1010) 2(=0010) F(=1111) C(=1100) E(=1110) 0(=0000) = 1010001011111100111000002
answer: A2FCE016 = 1010001011111100111000002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙165+2∙164+15∙163+12∙162+14∙161+0∙160 = 10∙1048576+2∙65536+15∙4096+12∙256+14∙16+0∙1 = 10485760+131072+61440+3072+224+0 = 1068156810
got It: A2FCE016 =1068156810
Translate the number 1068156810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
10681568 | 2 | | | | | | | | | | | | | | | | | | | | | | | |
-10681568 | 5340784 | 2 | | | | | | | | | | | | | | | | | | | | | | |
0 | -5340784 | 2670392 | 2 | | | | | | | | | | | | | | | | | | | | | |
| 0 | -2670392 | 1335196 | 2 | | | | | | | | | | | | | | | | | | | | |
| | 0 | -1335196 | 667598 | 2 | | | | | | | | | | | | | | | | | | | |
| | | 0 | -667598 | 333799 | 2 | | | | | | | | | | | | | | | | | | |
| | | | 0 | -333798 | 166899 | 2 | | | | | | | | | | | | | | | | | |
| | | | | 1 | -166898 | 83449 | 2 | | | | | | | | | | | | | | | | |
| | | | | | 1 | -83448 | 41724 | 2 | | | | | | | | | | | | | | | |
| | | | | | | 1 | -41724 | 20862 | 2 | | | | | | | | | | | | | | |
| | | | | | | | 0 | -20862 | 10431 | 2 | | | | | | | | | | | | | |
| | | | | | | | | 0 | -10430 | 5215 | 2 | | | | | | | | | | | | |
| | | | | | | | | | 1 | -5214 | 2607 | 2 | | | | | | | | | | | |
| | | | | | | | | | | 1 | -2606 | 1303 | 2 | | | | | | | | | | |
| | | | | | | | | | | | 1 | -1302 | 651 | 2 | | | | | | | | | |
| | | | | | | | | | | | | 1 | -650 | 325 | 2 | | | | | | | | |
| | | | | | | | | | | | | | 1 | -324 | 162 | 2 | | | | | | | |
| | | | | | | | | | | | | | | 1 | -162 | 81 | 2 | | | | | | |
| | | | | | | | | | | | | | | | 0 | -80 | 40 | 2 | | | | | |
| | | | | | | | | | | | | | | | | 1 | -40 | 20 | 2 | | | | |
| | | | | | | | | | | | | | | | | | 0 | -20 | 10 | 2 | | | |
| | | | | | | | | | | | | | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | | | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
1068156810 = 1010001011111100111000002
answer: A2FCE016 = 1010001011111100111000002