This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙160+2∙16-1+3∙16-2 = 0∙1+2∙0.0625+3∙0.00390625 = 0+0.125+0.01171875 = 0.1367187510
got It: 0.2316 =0.1367187510
Translate the number 0.1367187510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 13671875*8 |
1 | .09375*8 |
0 | .75*8 |
6 | .0*8 |
the result of the conversion was:
0.1367187510 = 0.1068
answer: 0.2316 = 0.1068
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
0.2316 = 0. 2 3 = 0(=0000). 2(=0010) 3(=0011) = .001000112
answer: 0.2316 = .001000112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
.0010001102 = . 001 000 110 = . 001(=1) 000(=0) 110(=6) = .1068
answer: 0.2316 = .1068