This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
14.4048 = 1 4. 4 0 4 = 1(=001) 4(=100). 4(=100) 0(=000) 4(=100) = 001100.1000001002
answer: 14.4048 = 1100.10000012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙81+4∙80+4∙8-1+0∙8-2+4∙8-3 = 1∙8+4∙1+4∙0.125+0∙0.015625+4∙0.001953125 = 8+4+0.5+0+0.0078125 = 12.507812510
got It: 14.4048 =12.507812510
Translate the number 12.507812510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
12 | 2 | | | |
-12 | 6 | 2 | | |
0 | -6 | 3 | 2 | |
| 0 | -2 | 1 | |
| | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 5078125*2 |
1 | .01563*2 |
0 | .03125*2 |
0 | .0625*2 |
0 | .125*2 |
0 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
12.507812510 = 1100.10000012
answer: 14.4048 = 1100.10000012