This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙164+15∙163+2∙162+4∙161+12∙160+5∙16-1 = 1∙65536+15∙4096+2∙256+4∙16+12∙1+5∙0.0625 = 65536+61440+512+64+12+0.3125 = 127564.312510
got It: 1F24C.516 =127564.312510
Translate the number 127564.312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
127564 | 8 | | | | | |
-127560 | 15945 | 8 | | | | |
4 | -15944 | 1993 | 8 | | | |
| 1 | -1992 | 249 | 8 | | |
| | 1 | -248 | 31 | 8 | |
| | | 1 | -24 | 3 | |
| | | | 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
127564.312510 = 371114.248
answer: 1F24C.516 = 371114.248
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1F24C.516 = 1 F 2 4 C. 5 = 1(=0001) F(=1111) 2(=0010) 4(=0100) C(=1100). 5(=0101) = 11111001001001100.01012
answer: 1F24C.516 = 11111001001001100.01012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011111001001001100.0101002 = 011 111 001 001 001 100. 010 100 = 011(=3) 111(=7) 001(=1) 001(=1) 001(=1) 100(=4). 010(=2) 100(=4) = 371114.248
answer: 1F24C.516 = 371114.248