This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
9∙162+6∙161+5∙160+10∙16-1+5∙16-2 = 9∙256+6∙16+5∙1+10∙0.0625+5∙0.00390625 = 2304+96+5+0.625+0.01953125 = 2405.6445312510
got It: 965.A516 =2405.6445312510
Translate the number 2405.6445312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2405 | 8 | | | |
-2400 | 300 | 8 | | |
5 | -296 | 37 | 8 | |
| 4 | -32 | 4 | |
| | 5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 64453125*8 |
5 | .15625*8 |
1 | .25*8 |
2 | .0*8 |
the result of the conversion was:
2405.6445312510 = 4545.5128
answer: 965.A516 = 4545.5128
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
965.A516 = 9 6 5. A 5 = 9(=1001) 6(=0110) 5(=0101). A(=1010) 5(=0101) = 100101100101.101001012
answer: 965.A516 = 100101100101.101001012
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
100101100101.1010010102 = 100 101 100 101. 101 001 010 = 100(=4) 101(=5) 100(=4) 101(=5). 101(=5) 001(=1) 010(=2) = 4545.5128
answer: 965.A516 = 4545.5128