This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110110112 = 011 011 011 = 011(=3) 011(=3) 011(=3) = 3338
answer: 110110112 = 3338
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+1∙24+1∙23+0∙22+1∙21+1∙20 = 0∙256+1∙128+1∙64+0∙32+1∙16+1∙8+0∙4+1∙2+1∙1 = 0+128+64+0+16+8+0+2+1 = 21910
got It: 0110110112 =21910
Translate the number 21910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
219 | 8 | | |
-216 | 27 | 8 | |
3 | -24 | 3 | |
| 3 | | |
|
the result of the conversion was:
21910 = 3338
answer: 110110112 = 3338