This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1101100010102 = 110 110 001 010 = 110(=6) 110(=6) 001(=1) 010(=2) = 66128
answer: 1101100010102 = 66128
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙211+1∙210+0∙29+1∙28+1∙27+0∙26+0∙25+0∙24+1∙23+0∙22+1∙21+0∙20 = 1∙2048+1∙1024+0∙512+1∙256+1∙128+0∙64+0∙32+0∙16+1∙8+0∙4+1∙2+0∙1 = 2048+1024+0+256+128+0+0+0+8+0+2+0 = 346610
got It: 1101100010102 =346610
Translate the number 346610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3466 | 8 | | | |
-3464 | 433 | 8 | | |
2 | -432 | 54 | 8 | |
| 1 | -48 | 6 | |
| | 6 | | |
|
the result of the conversion was:
346610 = 66128
answer: 1101100010102 = 66128