This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
0110.01108 = 0 1 1 0. 0 1 1 0 = 0(=000) 1(=001) 1(=001) 0(=000). 0(=000) 1(=001) 1(=001) 0(=000) = 000001001000.0000010010002
answer: 0110.01108 = 1001000.0000010012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙83+1∙82+1∙81+0∙80+0∙8-1+1∙8-2+1∙8-3+0∙8-4 = 0∙512+1∙64+1∙8+0∙1+0∙0.125+1∙0.015625+1∙0.001953125+0∙0.000244140625 = 0+64+8+0+0+0.015625+0.001953125+0 = 72.01757812510
got It: 0110.01108 =72.01757812510
Translate the number 72.01757812510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
72 | 2 | | | | | | |
-72 | 36 | 2 | | | | | |
0 | -36 | 18 | 2 | | | | |
| 0 | -18 | 9 | 2 | | | |
| | 0 | -8 | 4 | 2 | | |
| | | 1 | -4 | 2 | 2 | |
| | | | 0 | -2 | 1 | |
| | | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 017578125*2 |
0 | .03516*2 |
0 | .07031*2 |
0 | .14063*2 |
0 | .28125*2 |
0 | .5625*2 |
1 | .125*2 |
0 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
72.01757812510 = 1001000.0000010012
answer: 0110.01108 = 1001000.0000010012