This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
Baca16 = B a c a = B(=1011) a(=1010) c(=1100) a(=1010) = 10111010110010102
answer: Baca16 = 10111010110010102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
11∙163+10∙162+12∙161+10∙160 = 11∙4096+10∙256+12∙16+10∙1 = 45056+2560+192+10 = 4781810
got It: Baca16 =4781810
Translate the number 4781810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
47818 | 2 | | | | | | | | | | | | | | | |
-47818 | 23909 | 2 | | | | | | | | | | | | | | |
0 | -23908 | 11954 | 2 | | | | | | | | | | | | | |
| 1 | -11954 | 5977 | 2 | | | | | | | | | | | | |
| | 0 | -5976 | 2988 | 2 | | | | | | | | | | | |
| | | 1 | -2988 | 1494 | 2 | | | | | | | | | | |
| | | | 0 | -1494 | 747 | 2 | | | | | | | | | |
| | | | | 0 | -746 | 373 | 2 | | | | | | | | |
| | | | | | 1 | -372 | 186 | 2 | | | | | | | |
| | | | | | | 1 | -186 | 93 | 2 | | | | | | |
| | | | | | | | 0 | -92 | 46 | 2 | | | | | |
| | | | | | | | | 1 | -46 | 23 | 2 | | | | |
| | | | | | | | | | 0 | -22 | 11 | 2 | | | |
| | | | | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
4781810 = 10111010110010102
answer: Baca16 = 10111010110010102