This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101011100.0011102 = 101 011 100. 001 110 = 101(=5) 011(=3) 100(=4). 001(=1) 110(=6) = 534.168
answer: 101011100.001112 = 534.168
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+0∙27+1∙26+0∙25+1∙24+1∙23+1∙22+0∙21+0∙20+0∙2-1+0∙2-2+1∙2-3+1∙2-4+1∙2-5+0∙2-6 = 1∙256+0∙128+1∙64+0∙32+1∙16+1∙8+1∙4+0∙2+0∙1+0∙0.5+0∙0.25+1∙0.125+1∙0.0625+1∙0.03125+0∙0.015625 = 256+0+64+0+16+8+4+0+0+0+0+0.125+0.0625+0.03125+0 = 348.2187510
got It: 101011100.0011102 =348.2187510
Translate the number 348.2187510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
348 | 8 | | |
-344 | 43 | 8 | |
4 | -40 | 5 | |
| 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 21875*8 |
1 | .75*8 |
6 | .0*8 |
the result of the conversion was:
348.2187510 = 534.168
answer: 101011100.001112 = 534.168