This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
53248 = 5 3 2 4 = 5(=101) 3(=011) 2(=010) 4(=100) = 1010110101002
answer: 53248 = 1010110101002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙83+3∙82+2∙81+4∙80 = 5∙512+3∙64+2∙8+4∙1 = 2560+192+16+4 = 277210
got It: 53248 =277210
Translate the number 277210 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2772 | 2 | | | | | | | | | | | |
-2772 | 1386 | 2 | | | | | | | | | | |
0 | -1386 | 693 | 2 | | | | | | | | | |
| 0 | -692 | 346 | 2 | | | | | | | | |
| | 1 | -346 | 173 | 2 | | | | | | | |
| | | 0 | -172 | 86 | 2 | | | | | | |
| | | | 1 | -86 | 43 | 2 | | | | | |
| | | | | 0 | -42 | 21 | 2 | | | | |
| | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
277210 = 1010110101002
answer: 53248 = 1010110101002