This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010111.0111102 = 010 111. 011 110 = 010(=2) 111(=7). 011(=3) 110(=6) = 27.368
answer: 10111.011112 = 27.368
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+0∙23+1∙22+1∙21+1∙20+0∙2-1+1∙2-2+1∙2-3+1∙2-4+1∙2-5+0∙2-6 = 0∙32+1∙16+0∙8+1∙4+1∙2+1∙1+0∙0.5+1∙0.25+1∙0.125+1∙0.0625+1∙0.03125+0∙0.015625 = 0+16+0+4+2+1+0+0.25+0.125+0.0625+0.03125+0 = 23.4687510
got It: 010111.0111102 =23.4687510
Translate the number 23.4687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
23 | 8 | |
-16 | 2 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 46875*8 |
3 | .75*8 |
6 | .0*8 |
the result of the conversion was:
23.4687510 = 27.368
answer: 10111.011112 = 27.368