This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
819316 = 8 1 9 3 = 8(=1000) 1(=0001) 9(=1001) 3(=0011) = 10000001100100112
answer: 819316 = 10000001100100112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
8∙163+1∙162+9∙161+3∙160 = 8∙4096+1∙256+9∙16+3∙1 = 32768+256+144+3 = 3317110
got It: 819316 =3317110
Translate the number 3317110 в binary like this:
the Integer part of the number is divided by the base of the new number system:
33171 | 2 | | | | | | | | | | | | | | | |
-33170 | 16585 | 2 | | | | | | | | | | | | | | |
1 | -16584 | 8292 | 2 | | | | | | | | | | | | | |
| 1 | -8292 | 4146 | 2 | | | | | | | | | | | | |
| | 0 | -4146 | 2073 | 2 | | | | | | | | | | | |
| | | 0 | -2072 | 1036 | 2 | | | | | | | | | | |
| | | | 1 | -1036 | 518 | 2 | | | | | | | | | |
| | | | | 0 | -518 | 259 | 2 | | | | | | | | |
| | | | | | 0 | -258 | 129 | 2 | | | | | | | |
| | | | | | | 1 | -128 | 64 | 2 | | | | | | |
| | | | | | | | 1 | -64 | 32 | 2 | | | | | |
| | | | | | | | | 0 | -32 | 16 | 2 | | | | |
| | | | | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
3317110 = 10000001100100112
answer: 819316 = 10000001100100112