This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
110101.0102 = 110 101. 010 = 110(=6) 101(=5). 010(=2) = 65.28
answer: 110101.012 = 65.28
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+0∙23+1∙22+0∙21+1∙20+0∙2-1+1∙2-2+0∙2-3 = 1∙32+1∙16+0∙8+1∙4+0∙2+1∙1+0∙0.5+1∙0.25+0∙0.125 = 32+16+0+4+0+1+0+0.25+0 = 53.2510
got It: 110101.0102 =53.2510
Translate the number 53.2510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
53 | 8 | |
-48 | 6 | |
5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 25*8 |
2 | .0*8 |
the result of the conversion was:
53.2510 = 65.28
answer: 110101.012 = 65.28