This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0000101112 = 000 010 111 = 000(=0) 010(=2) 111(=7) = 0278
answer: 00101112 = 0278
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+0∙26+0∙25+1∙24+0∙23+1∙22+1∙21+1∙20 = 0∙256+0∙128+0∙64+0∙32+1∙16+0∙8+1∙4+1∙2+1∙1 = 0+0+0+0+16+0+4+2+1 = 2310
got It: 0000101112 =2310
Translate the number 2310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
23 | 8 | |
-16 | 2 | |
7 | | |
|
the result of the conversion was:
2310 = 278
answer: 00101112 = 278