This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
E8416 = E 8 4 = E(=1110) 8(=1000) 4(=0100) = 1110100001002
answer: E8416 = 1110100001002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
14∙162+8∙161+4∙160 = 14∙256+8∙16+4∙1 = 3584+128+4 = 371610
got It: E8416 =371610
Translate the number 371610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3716 | 2 | | | | | | | | | | | |
-3716 | 1858 | 2 | | | | | | | | | | |
0 | -1858 | 929 | 2 | | | | | | | | | |
| 0 | -928 | 464 | 2 | | | | | | | | |
| | 1 | -464 | 232 | 2 | | | | | | | |
| | | 0 | -232 | 116 | 2 | | | | | | |
| | | | 0 | -116 | 58 | 2 | | | | | |
| | | | | 0 | -58 | 29 | 2 | | | | |
| | | | | | 0 | -28 | 14 | 2 | | | |
| | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
371610 = 1110100001002
answer: E8416 = 1110100001002