This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
8∙161+8∙160 = 8∙16+8∙1 = 128+8 = 13610
got It: 8816 =13610
Translate the number 13610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
136 | 8 | | |
-136 | 17 | 8 | |
0 | -16 | 2 | |
| 1 | | |
|
the result of the conversion was:
13610 = 2108
answer: 8816 = 2108
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
8816 = 8 8 = 8(=1000) 8(=1000) = 100010002
answer: 8816 = 100010002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100010002 = 010 001 000 = 010(=2) 001(=1) 000(=0) = 2108
answer: 8816 = 2108