This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
7∙163+14∙162+0∙161+12∙160 = 7∙4096+14∙256+0∙16+12∙1 = 28672+3584+0+12 = 3226810
got It: 7E0C16 =3226810
Translate the number 3226810 в octal like this:
the Integer part of the number is divided by the base of the new number system:
32268 | 8 | | | | |
-32264 | 4033 | 8 | | | |
4 | -4032 | 504 | 8 | | |
| 1 | -504 | 63 | 8 | |
| | 0 | -56 | 7 | |
| | | 7 | | |
|
the result of the conversion was:
3226810 = 770148
the Final answer: 7E0C16 = 770148
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
7E0C16 = 7 E 0 C = 7(=0111) E(=1110) 0(=0000) C(=1100) = 1111110000011002
the Final answer: 7E0C16 = 1111110000011002
let\'s make a direct translation from binary to post-binary like this:
1111110000011002 = 111 111 000 001 100 = 111(=7) 111(=7) 000(=0) 001(=1) 100(=4) = 770148
the Final answer: 7E0C16 = 770148