This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
010010.1012 = 010 010. 101 = 010(=2) 010(=2). 101(=5) = 22.58
answer: 10010.1012 = 22.58
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+0∙23+0∙22+1∙21+0∙20+1∙2-1+0∙2-2+1∙2-3 = 0∙32+1∙16+0∙8+0∙4+1∙2+0∙1+1∙0.5+0∙0.25+1∙0.125 = 0+16+0+0+2+0+0.5+0+0.125 = 18.62510
got It: 010010.1012 =18.62510
Translate the number 18.62510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
18 | 8 | |
-16 | 2 | |
2 | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
0. | 625*8 |
5 | .0*8 |
the result of the conversion was:
18.62510 = 22.58
answer: 10010.1012 = 22.58