This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙87+0∙86+0∙85+1∙84+0∙83+0∙82+1∙81+0∙80 = 1∙2097152+0∙262144+0∙32768+1∙4096+0∙512+0∙64+1∙8+0∙1 = 2097152+0+0+4096+0+0+8+0 = 210125610
got It: 100100108 =210125610
Translate the number 210125610 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
2101256 | 16 | | | | | |
-2101248 | 131328 | 16 | | | | |
8 | -131328 | 8208 | 16 | | | |
| 0 | -8208 | 513 | 16 | | |
| | 0 | -512 | 32 | 16 | |
| | | 1 | -32 | 2 | |
| | | | 0 | | |
|
the result of the conversion was:
210125610 = 20100816
answer: 100100108 = 20100816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
100100108 = 1 0 0 1 0 0 1 0 = 1(=001) 0(=000) 0(=000) 1(=001) 0(=000) 0(=000) 1(=001) 0(=000) = 0010000000010000000010002
answer: 100100108 = 10000000010000000010002
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0010000000010000000010002 = 0010 0000 0001 0000 0000 1000 = 0010(=2) 0000(=0) 0001(=1) 0000(=0) 0000(=0) 1000(=8) = 20100816
answer: 0010000000010000000010008 = 20100816