This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
0010000000010000000010008 = 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 = 0(=000) 0(=000) 1(=001) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 1(=001) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 0(=000) 1(=001) 0(=000) 0(=000) 0(=000) = 0000000010000000000000000000000000010000000000000000000000000010000000002
answer: 0010000000010000000010008 = 10000000000000000000000000010000000000000000000000000010000000002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙823+0∙822+1∙821+0∙820+0∙819+0∙818+0∙817+0∙816+0∙815+0∙814+0∙813+1∙812+0∙811+0∙810+0∙89+0∙88+0∙87+0∙86+0∙85+0∙84+1∙83+0∙82+0∙81+0∙80 = 0∙5.9029581035871E+20+0∙7.3786976294838E+19+1∙9.2233720368548E+18+0∙1152921504606846976+0∙144115188075855872+0∙18014398509481984+0∙2251799813685248+0∙281474976710656+0∙35184372088832+0∙4398046511104+0∙549755813888+1∙68719476736+0∙8589934592+0∙1073741824+0∙134217728+0∙16777216+0∙2097152+0∙262144+0∙32768+0∙4096+1∙512+0∙64+0∙8+0∙1 = 0+0+9.2233720368548E+18+0+0+0+0+0+0+0+0+68719476736+0+0+0+0+0+0+0+0+512+0+0+0 = 9.2233721055743E+1810
got It: 0010000000010000000010008 =9.2233721055743E+1810
Translate the number 9.2233721055743E+1810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
9.2233721055743E+18 | 2 | |
0 | 0 | |
0 | | |
 |
the result of the conversion was:
9.2233721055743E+1810 = 002
answer: 0010000000010000000010008 = 002