This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01101011010101112 = 0110 1011 0101 0111 = 0110(=6) 1011(=B) 0101(=5) 0111(=7) = 6B5716
answer: 01101011010101112 = 6B5716
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+1∙214+1∙213+0∙212+1∙211+0∙210+1∙29+1∙28+0∙27+1∙26+0∙25+1∙24+0∙23+1∙22+1∙21+1∙20 = 0∙32768+1∙16384+1∙8192+0∙4096+1∙2048+0∙1024+1∙512+1∙256+0∙128+1∙64+0∙32+1∙16+0∙8+1∙4+1∙2+1∙1 = 0+16384+8192+0+2048+0+512+256+0+64+0+16+0+4+2+1 = 2747910
got It: 01101011010101112 =2747910
Translate the number 2747910 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
27479 | 16 | | | |
-27472 | 1717 | 16 | | |
7 | -1712 | 107 | 16 | |
| 5 | -96 | 6 | |
| | B | | |
 |
the result of the conversion was:
2747910 = 6B5716
answer: 01101011010101112 = 6B5716