This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
DCA16 = D C A = D(=1101) C(=1100) A(=1010) = 1101110010102
answer: DCA16 = 1101110010102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
13∙162+12∙161+10∙160 = 13∙256+12∙16+10∙1 = 3328+192+10 = 353010
got It: DCA16 =353010
Translate the number 353010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3530 | 2 | | | | | | | | | | | |
-3530 | 1765 | 2 | | | | | | | | | | |
0 | -1764 | 882 | 2 | | | | | | | | | |
| 1 | -882 | 441 | 2 | | | | | | | | |
| | 0 | -440 | 220 | 2 | | | | | | | |
| | | 1 | -220 | 110 | 2 | | | | | | |
| | | | 0 | -110 | 55 | 2 | | | | | |
| | | | | 0 | -54 | 27 | 2 | | | | |
| | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
353010 = 1101110010102
answer: DCA16 = 1101110010102