This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
13∙162+12∙161+10∙160 = 13∙256+12∙16+10∙1 = 3328+192+10 = 353010
got It: DCA16 =353010
Translate the number 353010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3530 | 8 | | | |
-3528 | 441 | 8 | | |
2 | -440 | 55 | 8 | |
| 1 | -48 | 6 | |
| | 7 | | |
|
the result of the conversion was:
353010 = 67128
answer: DCA16 = 67128
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
DCA16 = D C A = D(=1101) C(=1100) A(=1010) = 1101110010102
answer: DCA16 = 1101110010102
let\'s make a direct translation from binary to post-binary like this:
1101110010102 = 110 111 001 010 = 110(=6) 111(=7) 001(=1) 010(=2) = 67128
answer: DCA16 = 67128