This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010100011102 = 001 010 001 110 = 001(=1) 010(=2) 001(=1) 110(=6) = 12168
answer: 10100011102 = 12168
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+1∙29+0∙28+1∙27+0∙26+0∙25+0∙24+1∙23+1∙22+1∙21+0∙20 = 0∙2048+0∙1024+1∙512+0∙256+1∙128+0∙64+0∙32+0∙16+1∙8+1∙4+1∙2+0∙1 = 0+0+512+0+128+0+0+0+8+4+2+0 = 65410
got It: 0010100011102 =65410
Translate the number 65410 в octal like this:
the Integer part of the number is divided by the base of the new number system:
| 654 | 8 | | | |
| -648 | 81 | 8 | | |
| 6 | -80 | 10 | 8 | |
| 1 | -8 | 1 | |
| | 2 | | |
 |
the result of the conversion was:
65410 = 12168
answer: 10100011102 = 12168