This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙83+0∙82+1∙81+7∙80 = 1∙512+0∙64+1∙8+7∙1 = 512+0+8+7 = 52710
got It: 10178 =52710
Translate the number 52710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
527 | 16 | | |
-512 | 32 | 16 | |
F | -32 | 2 | |
| 0 | | |
|
the result of the conversion was:
52710 = 20F16
answer: 10178 = 20F16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
10178 = 1 0 1 7 = 1(=001) 0(=000) 1(=001) 7(=111) = 0010000011112
answer: 10178 = 10000011112
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0010000011112 = 0010 0000 1111 = 0010(=2) 0000(=0) 1111(=F) = 20F16
answer: 0010000011118 = 20F16