This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
10178 = 1 0 1 7 = 1(=001) 0(=000) 1(=001) 7(=111) = 0010000011112
answer: 10178 = 10000011112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙83+0∙82+1∙81+7∙80 = 1∙512+0∙64+1∙8+7∙1 = 512+0+8+7 = 52710
got It: 10178 =52710
Translate the number 52710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
527 | 2 | | | | | | | | | |
-526 | 263 | 2 | | | | | | | | |
1 | -262 | 131 | 2 | | | | | | | |
| 1 | -130 | 65 | 2 | | | | | | |
| | 1 | -64 | 32 | 2 | | | | | |
| | | 1 | -32 | 16 | 2 | | | | |
| | | | 0 | -16 | 8 | 2 | | | |
| | | | | 0 | -8 | 4 | 2 | | |
| | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | 0 | -2 | 1 | |
| | | | | | | | 0 | | |
|
the result of the conversion was:
52710 = 10000011112
answer: 10178 = 10000011112