This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙167+0∙166+0∙165+0∙164+1∙163+0∙162+0∙161+0∙160 = 0∙268435456+0∙16777216+0∙1048576+0∙65536+1∙4096+0∙256+0∙16+0∙1 = 0+0+0+0+4096+0+0+0 = 409610
got It: 0000100016 =409610
Translate the number 409610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
4096 | 8 | | | | |
-4096 | 512 | 8 | | | |
0 | -512 | 64 | 8 | | |
| 0 | -64 | 8 | 8 | |
| | 0 | -8 | 1 | |
| | | 0 | | |
 |
the result of the conversion was:
409610 = 100008
answer: 0000100016 = 100008
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
0000100016 = 0 0 0 0 1 0 0 0 = 0(=0000) 0(=0000) 0(=0000) 0(=0000) 1(=0001) 0(=0000) 0(=0000) 0(=0000) = 10000000000002
answer: 0000100016 = 10000000000002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010000000000002 = 001 000 000 000 000 = 001(=1) 000(=0) 000(=0) 000(=0) 000(=0) = 100008
answer: 0000100016 = 100008