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# Transfer 000100110010.01011100 from hexadecimal in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

First we will perform the translation through the decimal system

let\'s translate to decimal like this:

0∙1611+0∙1610+0∙169+1∙168+0∙167+0∙166+1∙165+1∙164+0∙163+0∙162+1∙161+0∙160+0∙16-1+1∙16-2+0∙16-3+1∙16-4+1∙16-5+1∙16-6+0∙16-7+0∙16-8 = 0∙17592186044416+0∙1099511627776+0∙68719476736+1∙4294967296+0∙268435456+0∙16777216+1∙1048576+1∙65536+0∙4096+0∙256+1∙16+0∙1+0∙0.0625+1∙0.00390625+0∙0.000244140625+1∙1.52587890625E-5+1∙9.5367431640625E-7+1∙5.9604644775391E-8+0∙3.7252902984619E-9+0∙2.3283064365387E-10 = 0+0+0+4294967296+0+0+1048576+65536+0+0+16+0+0+0.00390625+0+1.52587890625E-5+9.5367431640625E-7+5.9604644775391E-8+0+0 = 4296081424.003922522068023710

got It: 000100110010.0101110016 =4296081424.003922522068023710

Translate the number 4296081424.003922522068023710 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 4296081424 8 -4296081424 537010178 8 0 -537010176 67126272 8 2 -67126272 8390784 8 0 -8390784 1048848 8 0 -1048848 131106 8 0 -131104 16388 8 2 -16384 2048 8 4 -2048 256 8 0 -256 32 8 0 -32 4 0

the Fractional part of the number is multiplied by the base of the new number system:

 0. 0039225220680237*8 0 .03138*8 0 .25104*8 2 .00833*8 0 .06665*8 0 .5332*8 4 .26563*8 2 .125*8 1 .0*8 2 .0*8

the result of the conversion was:

4296081424.003922522068023710 = 40004200020.0020042128
answer: 000100110010.0101110016 = 40004200020.0020042128

Now we will perform a direct translation.

let\'s do a direct translation from hexadecimal to binary like this:

000100110010.0101110016 = 0 0 0 1 0 0 1 1 0 0 1 0. 0 1 0 1 1 1 0 0 = 0(=0000) 0(=0000) 0(=0000) 1(=0001) 0(=0000) 0(=0000) 1(=0001) 1(=0001) 0(=0000) 0(=0000) 1(=0001) 0(=0000). 0(=0000) 1(=0001) 0(=0000) 1(=0001) 1(=0001) 1(=0001) 0(=0000) 0(=0000) = 100000000000100010000000000010000.0000000100000001000100012

answer: 000100110010.0101110016 = 100000000000100010000000000010000.0000000100000001000100012

let\'s make a direct translation from binary to post-binary like this:

100000000000100010000000000010000.0000000100000001000100012 = 100 000 000 000 100 010 000 000 000 010 000. 000 000 010 000 000 100 010 001 = 100(=4) 000(=0) 000(=0) 000(=0) 100(=4) 010(=2) 000(=0) 000(=0) 000(=0) 010(=2) 000(=0). 000(=0) 000(=0) 010(=2) 000(=0) 000(=0) 100(=4) 010(=2) 001(=1) = 40004200020.002004218

answer: 000100110010.0101110016 = 40004200020.002004218