This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01101111101011102 = 0110 1111 1010 1110 = 0110(=6) 1111(=F) 1010(=A) 1110(=E) = 6FAE16
answer: 01101111101011102 = 6FAE16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+1∙214+1∙213+0∙212+1∙211+1∙210+1∙29+1∙28+1∙27+0∙26+1∙25+0∙24+1∙23+1∙22+1∙21+0∙20 = 0∙32768+1∙16384+1∙8192+0∙4096+1∙2048+1∙1024+1∙512+1∙256+1∙128+0∙64+1∙32+0∙16+1∙8+1∙4+1∙2+0∙1 = 0+16384+8192+0+2048+1024+512+256+128+0+32+0+8+4+2+0 = 2859010
got It: 01101111101011102 =2859010
Translate the number 2859010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
28590 | 16 | | | |
-28576 | 1786 | 16 | | |
E | -1776 | 111 | 16 | |
| A | -96 | 6 | |
| | F | | |
 |
the result of the conversion was:
2859010 = 6FAE16
answer: 01101111101011102 = 6FAE16