This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙84+4∙83+5∙82+3∙81+5∙80 = 1∙4096+4∙512+5∙64+3∙8+5∙1 = 4096+2048+320+24+5 = 649310
got It: 145358 =649310
Translate the number 649310 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
6493 | 16 | | | |
-6480 | 405 | 16 | | |
D | -400 | 25 | 16 | |
| 5 | -16 | 1 | |
| | 9 | | |
|
the result of the conversion was:
649310 = 195D16
answer: 145358 = 195D16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
145358 = 1 4 5 3 5 = 1(=001) 4(=100) 5(=101) 3(=011) 5(=101) = 0011001010111012
answer: 145358 = 11001010111012
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00011001010111012 = 0001 1001 0101 1101 = 0001(=1) 1001(=9) 0101(=5) 1101(=D) = 195D16
answer: 00011001010111018 = 195D16