This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
8∙163+8∙162+9∙161+7∙160 = 8∙4096+8∙256+9∙16+7∙1 = 32768+2048+144+7 = 3496710
got It: 889716 =3496710
Translate the number 3496710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
34967 | 8 | | | | | |
-34960 | 4370 | 8 | | | | |
7 | -4368 | 546 | 8 | | | |
| 2 | -544 | 68 | 8 | | |
| | 2 | -64 | 8 | 8 | |
| | | 4 | -8 | 1 | |
| | | | 0 | | |
|
the result of the conversion was:
3496710 = 1042278
answer: 889716 = 1042278
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
889716 = 8 8 9 7 = 8(=1000) 8(=1000) 9(=1001) 7(=0111) = 10001000100101112
answer: 889716 = 10001000100101112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010001000100101112 = 001 000 100 010 010 111 = 001(=1) 000(=0) 100(=4) 010(=2) 010(=2) 111(=7) = 1042278
answer: 889716 = 1042278