This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
1078 = 1 0 7 = 1(=001) 0(=000) 7(=111) = 0010001112
answer: 1078 = 10001112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙82+0∙81+7∙80 = 1∙64+0∙8+7∙1 = 64+0+7 = 7110
got It: 1078 =7110
Translate the number 7110 в binary like this:
the Integer part of the number is divided by the base of the new number system:
71 | 2 | | | | | | |
-70 | 35 | 2 | | | | | |
1 | -34 | 17 | 2 | | | | |
| 1 | -16 | 8 | 2 | | | |
| | 1 | -8 | 4 | 2 | | |
| | | 0 | -4 | 2 | 2 | |
| | | | 0 | -2 | 1 | |
| | | | | 0 | | |
 |
the result of the conversion was:
7110 = 10001112
answer: 1078 = 10001112