This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011101011012 = 001 110 101 101 = 001(=1) 110(=6) 101(=5) 101(=5) = 16558
answer: 11101011012 = 16558
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+1∙29+1∙28+1∙27+0∙26+1∙25+0∙24+1∙23+1∙22+0∙21+1∙20 = 0∙2048+0∙1024+1∙512+1∙256+1∙128+0∙64+1∙32+0∙16+1∙8+1∙4+0∙2+1∙1 = 0+0+512+256+128+0+32+0+8+4+0+1 = 94110
got It: 0011101011012 =94110
Translate the number 94110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
941 | 8 | | | |
-936 | 117 | 8 | | |
5 | -112 | 14 | 8 | |
| 5 | -8 | 1 | |
| | 6 | | |
|
the result of the conversion was:
94110 = 16558
answer: 11101011012 = 16558