This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
5∙163+11∙162+13∙161+14∙160 = 5∙4096+11∙256+13∙16+14∙1 = 20480+2816+208+14 = 2351810
got It: 5BDE16 =2351810
Translate the number 2351810 в octal like this:
the Integer part of the number is divided by the base of the new number system:
23518 | 8 | | | | |
-23512 | 2939 | 8 | | | |
6 | -2936 | 367 | 8 | | |
| 3 | -360 | 45 | 8 | |
| | 7 | -40 | 5 | |
| | | 5 | | |
|
the result of the conversion was:
2351810 = 557368
answer: 5BDE16 = 557368
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
5BDE16 = 5 B D E = 5(=0101) B(=1011) D(=1101) E(=1110) = 1011011110111102
answer: 5BDE16 = 1011011110111102
let\'s make a direct translation from binary to post-binary like this:
1011011110111102 = 101 101 111 011 110 = 101(=5) 101(=5) 111(=7) 011(=3) 110(=6) = 557368
answer: 5BDE16 = 557368