This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙161+13∙160+6∙16-1+10∙16-2 = 15∙16+13∙1+6∙0.0625+10∙0.00390625 = 240+13+0.375+0.0390625 = 253.414062510
got It: FD.6A16 =253.414062510
Translate the number 253.414062510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
253 | 8 | | |
-248 | 31 | 8 | |
5 | -24 | 3 | |
| 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 4140625*8 |
3 | .3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
253.414062510 = 375.3248
answer: FD.6A16 = 375.3248
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
FD.6A16 = F D. 6 A = F(=1111) D(=1101). 6(=0110) A(=1010) = 11111101.01101012
answer: FD.6A16 = 11111101.01101012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011111101.0110101002 = 011 111 101. 011 010 100 = 011(=3) 111(=7) 101(=5). 011(=3) 010(=2) 100(=4) = 375.3248
answer: FD.6A16 = 375.3248