This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
25.5548 = 2 5. 5 5 4 = 2(=010) 5(=101). 5(=101) 5(=101) 4(=100) = 010101.1011011002
answer: 25.5548 = 10101.10110112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙81+5∙80+5∙8-1+5∙8-2+4∙8-3 = 2∙8+5∙1+5∙0.125+5∙0.015625+4∙0.001953125 = 16+5+0.625+0.078125+0.0078125 = 21.710937510
got It: 25.5548 =21.710937510
Translate the number 21.710937510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
| 21 | 2 | | | | |
| -20 | 10 | 2 | | | |
| 1 | -10 | 5 | 2 | | |
| 0 | -4 | 2 | 2 | |
| | 1 | -2 | 1 | |
| | | 0 | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 7109375*2 |
| 1 | .42188*2 |
| 0 | .84375*2 |
| 1 | .6875*2 |
| 1 | .375*2 |
| 0 | .75*2 |
| 1 | .5*2 |
| 1 | .0*2 |
the result of the conversion was:
21.710937510 = 10101.10110112
answer: 25.5548 = 10101.10110112