This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
2318 = 2 3 1 = 2(=010) 3(=011) 1(=001) = 0100110012
answer: 2318 = 100110012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙82+3∙81+1∙80 = 2∙64+3∙8+1∙1 = 128+24+1 = 15310
got It: 2318 =15310
Translate the number 15310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
| 153 | 2 | | | | | | | |
| -152 | 76 | 2 | | | | | | |
| 1 | -76 | 38 | 2 | | | | | |
| 0 | -38 | 19 | 2 | | | | |
| | 0 | -18 | 9 | 2 | | | |
| | | 1 | -8 | 4 | 2 | | |
| | | | 1 | -4 | 2 | 2 | |
| | | | | 0 | -2 | 1 | |
| | | | | | 0 | | |
 |
the result of the conversion was:
15310 = 100110012
answer: 2318 = 100110012