This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
6548 = 6 5 4 = 6(=110) 5(=101) 4(=100) = 1101011002
answer: 6548 = 1101011002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙82+5∙81+4∙80 = 6∙64+5∙8+4∙1 = 384+40+4 = 42810
got It: 6548 =42810
Translate the number 42810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
| 428 | 2 | | | | | | | | |
| -428 | 214 | 2 | | | | | | | |
| 0 | -214 | 107 | 2 | | | | | | |
| 0 | -106 | 53 | 2 | | | | | |
| | 1 | -52 | 26 | 2 | | | | |
| | | 1 | -26 | 13 | 2 | | | |
| | | | 0 | -12 | 6 | 2 | | |
| | | | | 1 | -6 | 3 | 2 | |
| | | | | | 0 | -2 | 1 | |
| | | | | | | 1 | | |
 |
the result of the conversion was:
42810 = 1101011002
answer: 6548 = 1101011002